Difference between revisions of "MR 02 Loesung"

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<math>2^2 + 2 = 6</math>
 
<math>2^2 + 2 = 6</math>
 +
 +
<math>(2 + {2 \over 2})! = 6</math>
  
 
<math> \binom{2 \cdot 2}{2} = 6 </math>
 
<math> \binom{2 \cdot 2}{2} = 6 </math>

Revision as of 11:34, 21 March 2013

Drei Zahlen

Für den Rest aller ganzen Zahlen