Difference between revisions of "MR 02 Loesung"

Revision as of 09:30, 17 March 2013

$(0!+0!+0!)!=6$

$(1+1+1)!=6$

$2+2+2=6$

$3!{3 \over 3}=6$

$({\sqrt[{3}]{3^{3}}})!=6$

${\sqrt {4}}+{\sqrt {4}}+{\sqrt {4}}=6$

$5+{5 \over 5}=6$

$6{6 \over 6}=6$

${\sqrt[{6}]{6^{6}}}=6$

$7-{7 \over 7}=6$

$({\sqrt {8+{8 \over 8}}})!=6$

$({\sqrt {9}})!{9 \over 9}=6$

$(\log 10+\log 10+\log 10)!=6$

Für den Rest aller ganzen Zahlen

$\left|\cos n\pi +\cos n\pi +\cos n\pi \right|!=6~\forall ~n\in \mathbb {Z}$

$(n(n-n)-e^{i\pi }-e^{i\pi }-e^{i\pi })!=6~\forall ~n\in \mathbb {Z}$

@@ Line 8: / Line 8: @@
 <math>3! {3 \over 3} = 6</math>
+<math>(\sqrt[3]{3^3})! = 6</math>
 <math>\sqrt{4} + \sqrt{4} + \sqrt{4} = 6</math>
@@ Line 14: / Line 16: @@
 <math>6 {6 \over 6} = 6</math>
+<math>\sqrt[6]{6^6} = 6</math>
 <math>7 - {7 \over 7} = 6</math>