Rolands Lösung für MR_02.
Die folgenden Ausdrücke haben alle den Wert 6.
( 1 + 1 + 1 ) ! {\displaystyle {(1+1+1)!}} 3 ⋅ 3 − 3 {\displaystyle 3\cdot 3-3} 4 + 4 ⋅ 4 {\displaystyle 4+{\sqrt {\sqrt {4\cdot 4}}}} 5 + 5 5 {\displaystyle 5+{\frac {5}{5}}} 6 6 6 {\displaystyle 6^{\frac {6}{6}}} 7 − 7 7 {\displaystyle 7-{\frac {7}{7}}} ⌈ 8 + 8 8 ⌉ {\displaystyle \left\lceil {\frac {8+8}{\sqrt {8}}}\right\rceil } 9 + 9 9 {\displaystyle {\frac {9+9}{\sqrt {9}}}}
