MR 01 Loesung

Fossys Lösung für das Rätsel MR_01.

Lösung in $\mathbb {C}$

$f_{1}(z)={\frac {\left|z\right|^{2}}{z}}$	$={\bar {z}}$
$f_{2}(z)={\frac {i\left|z\right|^{2}}{z}}$	Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = \Re\gtrless\Im(z)}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f_3(z) = \frac{z^2 + \left | z \right |^2}{2z}}	Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle = \Re(z)}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f_4(z) = \frac{z^2 - \left | z \right |^2}{2i z}}	$=\Im (z)$

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \forall z \in \C\setminus\{0\}}