Difference between revisions of "MR 01 Loesung"
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(Created page with "== Lösung in <math>\C</math> == <math>\begin{array}{c c c c c} f_1(z) & = & \frac{\left | z \right |^2}{z} & = & \bar{z} \\ f_2(z) & = & \frac{i \left | z \right |^2}{z…") |
m (Link zum Rätsel eingefügt.) |
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| + | Fossys Lösung für das Rätsel [[MR_01]]. | ||
| + | |||
== Lösung in <math>\C</math> == | == Lösung in <math>\C</math> == | ||
| − | <math> | + | {| |
| − | f_1(z) | + | | <math>f_1(z) = \frac{\left | z \right |^2}{z}</math> |
| − | f_2(z) | + | | <math>= \bar{z}</math> |
| − | f_3(z) | + | |- |
| − | f_4(z) | + | | <math>f_2(z) = \frac{i \left | z \right |^2}{z}</math> |
| − | \ | + | | <math>= \Re\gtrless\Im(z)</math> |
| + | |- | ||
| + | | <math>f_3(z) = \frac{z^2 + \left | z \right |^2}{2z}</math> | ||
| + | | <math>= \Re(z)</math> | ||
| + | |- | ||
| + | | <math>f_4(z) = \frac{z^2 - \left | z \right |^2}{2i z}</math> | ||
| + | | <math>= \Im(z)</math> | ||
| + | |} | ||
| + | |||
| + | <math>\forall z \in \C\setminus\{0\}</math> | ||
