Difference between revisions of "MR 05 Loesung"

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Line 14: Line 14:
 
<math>3y = x</math>
 
<math>3y = x</math>
  
<math>3y = sqrt(1 - y^2)</math>
+
<math>3y = \sqrt{1 - y^2}</math>

Revision as of 18:16, 10 January 2018

Advendkranz drehen

zurück zur Aufgabenstellung

So sieht der Kranz mathematisch aus. Das rote sind die Kerzen. Die jeweiligen Dreiecke sind deckungsgleich und die blauen und orangenen Linien sind gleich lang.

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Adventkranz mathematisch

Man sieht sofort, dass die beiden äußeren Kerzen den Abstand Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle x-y} und die beiden innern Kerzen den Abstand Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2y} haben. Des weiteren fällt auf, dass (wegen r=1) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x^2 + y^2 = 1^2} ist.

Die beiden inneren Kerzen und die äußeren mussen laut Aufgabenstellung den gleichen Abstand haben.

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2y = x - y}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3y = x}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3y = \sqrt{1 - y^2}}