Difference between revisions of "MR 01 Loesung"

Revision as of 18:03, 5 July 2012

@@ Line 1: / Line 1: @@
 == Lösung in <math>\C</math> ==
-<math>\begin{array}{c c c c c}
+{|
-f_1(z) & = & \frac{\left | z \right |^2}{z}        & = & \bar{z} \\
+| <math>f_1(z)</math>
-f_2(z) & = & \frac{i \left | z \right |^2}{z}      & = & \Re<>\Im(z) \\
+| =
-f_3(z) & = & \frac{z^2 + \left | z \right |^2}{2z} & = & \Re(z) \\
+| <math>\frac{\left | z \right |^2}{z}</math>
-f_4(z) & = & \frac{z^2 - \left | z \right |^2}{2z} & = & \Im(z) \\
+| =
-\end{array}</math>
+| <math>\bar{z}</math>
+|-
+| <math>f_2(z)</math>
+| =
+| <math>\frac{i \left | z \right |^2}{z}</math>
+| =
+| <math>\Re<>\Im(z)</math>
+|-
+| <math>f_3(z)</math>
+|  =
+| <math>\frac{z^2 + \left | z \right |^2}{2z}</math>
+| =
+| <math>\Re(z)</math>
+|-
+| <math>f_4(z)</math>
+| =
+| <math>\frac{z^2 - \left | z \right |^2}{2z}</math>
+| =
+| <math>\Im(z)</math>
+|}